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8x+2x^2=154
We move all terms to the left:
8x+2x^2-(154)=0
a = 2; b = 8; c = -154;
Δ = b2-4ac
Δ = 82-4·2·(-154)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*2}=\frac{28}{4} =7 $
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